Notes
Slide Show
Outline
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 Just in Time Algebra with Multimedia:  Context Based, with Animation!
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"Walter R."
  • Walter R. Hunter             whunter@mc3.edu
  • Roseanne S. Hofmann     rhofman@mc3.edu
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Just in Time Algebra

  • Philosophy of the the course:
      •   Applications should not only motivate, but also give concrete examples to the abstract mathematical concepts of the course.

  • AMATYC Standards:
  •   Problems should be solved numerically,             graphically, symbolically, and verbally.



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Just in Time Algebra

  • Statistics:








  •   Day students taught by full time faculty.
  •   p-value 0.000000121 for average grade.

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Just in Time Algebra

  • Statistics:








  •   Day students taught by full time faculty.
  •   p-value 0.0047 for average grade.

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Just in Time Algebra
  • Statistics:  Intermediate Algebra









  • Day students taught by full time faculty and   passed Beginning Algebra the previous semester.
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Benefits for Adjuncts
  • Keep current on the “standards”
  • Textbook provides flexible teaching modes
    • Lecture materials
    • Group Work
    • Homework Exercises
  • Multimedia matches textbook
  • Smartboard lectures ready made
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Time Line of Development
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Sign Numbers
  • 1.   You have $10 and you owe the IRS $25, what is your net worth?


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Sign Numbers
  • 1.   You have $10 and you owe the IRS $25, what is your net worth?
  • 10 - 25 = -15


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Sign Numbers
  • 1.   You have $10 and you owe the IRS $25, what is your net worth?
  • 10 - 25 = -15
  • 2.   You loose $5 a day for the next three days, how much money will you loose?
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Sign Numbers
  • 1.   You have $10 and you owe the IRS $25, what is your net worth?
  • 10 - 25 = -15
  • 2.   You loose $5 a day for the next three days, how much money will you loose?
  • -5 ( 3 ) = - 15


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Sign Numbers
  • 1.   You have $10 and you owe the IRS $25, what is your net worth?
  • 10 - 25 = -15
  • 2.   You loose $5 a day for the next three days, how much money will you loose?
  • -5 ( 3 ) = - 15
  • 3.   You lost $7 for the last six days, how much more money did you have six days ago?
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Sign Numbers
  • 1.   You have $10 and you owe the IRS $25, what is your net worth?
  • 10 - 25 = -15
  • 2.   You loose $5 a day for the next three days, how much money will you loose?
  • -5 ( 3 ) = - 15
  • 3.   You lost $7 for the last six days, how much more money did you have six days ago?
  • ( - 7 )( - 6 ) = 42
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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.







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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.







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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.








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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.







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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.








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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.








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Introduction to Variables
  •   A truck rental company, WE-HAUL, charges $21.95 plus 41 cents per mile.







  • The equation relating cost and miles driven:
  • C = .41m + 21.95
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"What is"
  •   What is  the equation that relates weight and height?  Simplify  the equation.


  • W = 5( h - 60 ) + 100
  •                     W = 5h - 300 + 100
  •                     W = 5h - 200
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"How tall should you be..."
  •    How tall should you be if you weigh 135 lbs?
  • Find h if W = 135
  •                               135 = 5h - 200
  •                     135 + 200 = 5h - 200 + 200
  •                               335 = 5h
  •                            335/5 = 5h/5
  •                                 67 = h
  •   You should be 5 feet 7 inches tall if you weigh 135 lbs.
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"How tall should you be..."
  • How tall should you be if you weigh  0 lbs?
  • Find h if W = 0
  •                            0 = 5h - 200
  •                  0 + 200 = 5h - 200 + 200
  •                        200 = 5h
  •                     200/5 = 5h/5
  •                          40 = h
  •    Does this answer makes sense?
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"Solve for h from the..."
  • Solve for h from the formula in part 1b.
  •                              W = 5h - 200
  •                    W + 200 = 5h - 200 +200
  •                    W + 200 = 5h
  •               (W + 200)/5 = 5h/5
  •               (W + 200)/5 = h
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Applications of Linear Equations - Percent
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 Applications of Inequalities
  • Two companies offer you very similar positions.  Random House will pay you $10,000 a year plus 7% commission on the dollar amount of book sales.  Moore Publishing Co. will pay you $8,000 a year plus 11% commission.               Random House   SALES     CALCULATION         INCOME
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 Applications of Inequalities
  • Two companies offer you very similar positions.  Random House will pay you $10,000 a year plus 7% commission on the dollar amount of book sales.  Moore Publishing Co. will pay you $8,000 a year plus 11% commission.               Random House   SALES     CALCULATION         INCOME  100,000   .07(100,000) + 10,000        17,000
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 Applications of Inequalities
  • Two companies offer you very similar positions.  Random House will pay you $10,000 a year plus 7% commission on the dollar amount of book sales.  Moore Publishing Co. will pay you $8,000 a year plus 11% commission.               Random House   SALES     CALCULATION         INCOME  100,000   .07(100,000) + 10,000        17,000  S             .07S + 10,000                     I
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"For what dollar amount of..."
  • For what dollar amount of book sales does Random House pay more than Moore Publishing Co.?
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"For what dollar amount of..."
  • For what dollar amount of book sales does Random House pay more than Moore Publishing Co.?
  • Income from R.H. > Income from Moore
  •           .07S + 10000 > .11S + 8000
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"For what dollar amount of..."
  • For what dollar amount of book sales does Random House pay more than Moore Publishing Co.?
  • Income from R.H. > Income from Moore
  •           .07S + 10000 > .11S + 8000
  •             .07S + 2000 > .11S
  •                        2000 > .04S
  •                     50,000 > S
  • Random House will pay more for sales less  than $50,000.
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"When NASA sends a rocket..."
  • When NASA sends a rocket into space, they monitor the temperature of certain gases. Time is the independent variable and temperature is the dependent variable.  Notice that negative time is used to denote time before lift off.        Time      Temp          Time      Temp  -20          -20               10           80         -15        -20               15           120 -10          -10               20           90   -5          0                 25           25    0            15                30            5    5            40                35           -15
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 Scatter Plots
    •            TEMP




  •               MIN




  • What was the temperature at take off?





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 Scatter Plots
    •            TEMP




  •               MIN




  • When was the temperature zero?





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"An appliance repair shop charges..."
  • An appliance repair shop charges an initial fee of $30 plus $15 per hour to fix an appliance.
  • Complete the table to find the cost of repairing an appliance.
  • Hours           Calculation      Costs    3 15(3) + 30         75 5 15(5) + 30        105 10 15(10) + 30      180 t 15t + 30         C
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"Use the results in part..."
  • Use the results in part a. to graph the equation in part b.  Choose an appropriate scale and only graph the portion that makes sense to the problem. Label the axis.


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"Use the results in part..."
  • Use the results in part a. to graph the equation in part b.  Choose an appropriate scale and only graph the portion that makes sense to the problem. Label the axis.


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"Sally has a lawn-mowing business..."
  • Sally has a lawn-mowing business for the summer.  She bought a lawn mower for $200 and she charges $5 an hour.  The equation that relates profit and hours worked is               p = 5h - 200.
  • How many hours does she have to work to break even?
  • Find h, if p = 0.
  •                     0 = 5h - 200
  •                 40 = h
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"Sally has a lawn-mowing business..."
  • Sally has a lawn-mowing business for the summer.  She bought a lawn mower for $200 and she charges $5 an hour.  The equation that relates profit and hours worked is               p = 5h - 200.
  • How much money will she lose if she doesn’t work any hours?
  • Find p, if h = 0.
  •                 p = 5( 0) - 200
  •                 p = -200
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"Graph the line p =..."
  • Graph the line p = 5h - 200 by plotting the points obtained in parts a. and b.  Choose an appropriate scale and only graph the portion that makes sense to the problem.  Label the axis.
  • Break even point (40, 0 ).
  • Starting costs (0, -200 ).





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Introduction to Slope
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Introduction to Slope
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Introduction to Slope
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Introduction to Slope
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Introduction to Slope
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Introduction to Slope
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 Introduction to Slope
  • Which grow faster: Hybrid A corn seedlings, which grew 14.6 centimeters in 15 days, or Hybrid B, which grew 11.2 centimeters in 12 days.
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 Introduction to Slope
  • Which grow faster: Hybrid A corn seedlings, which grew 14.6 centimeters in 15 days, or Hybrid B, which grew 11.2 centimeters in 12 days.
  • Find how fast they grow per day.
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 Introduction to Slope
  • Which grow faster: Hybrid A corn seedlings, which grew 14.6 centimeters in 15 days, or Hybrid B, which grew 11.2 centimeters in 12 days.
  • Find how fast they grow per day.
  • Hybrid A: 14.6/15 =
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 Introduction to Slope
  • Which grow faster: Hybrid A corn seedlings, which grew 14.6 centimeters in 15 days, or Hybrid B, which grew 11.2 centimeters in 12 days.
  • Find how fast they grow per day.
  • Hybrid A: 14.6/15 =
  •                 14.6/15 = .9733
  • Hybrid A grew an average of .9733 centimeters per day.
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Applications of Graphs
  • You are going to rent a car for a day.  You have two choices, Wrecker Car company or Caddie Car Rental.  Wrecker charges $20 a day and $0.75 a mile, while Caddie charges $27 a day and $0.40 a mile.
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Applications of Graphs
  • You are going to rent a car for a day.  You have two choices, Wrecker Car company or Caddie Car Rental.  Wrecker charges $20 a day and $0.75 a mile, while Caddie charges $27 a day and $0.40 a mile.
  • Write an equation for the cost of renting a car from each company.
  • Wrecker:  C = .75m + 20
  • Caddie:    C = .40m + 27
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"Graph both equations on the..."
  • Graph both equations on the same set of axis.  Label each axis and choose an appropriate scale.  Only graph the portion that is relevant to the problem.
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
  • How far do you have drive for the two companies to charge the same?
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
  • How far do you have drive for the two companies to charge the same?
  • .75M + 20 = .40M + 27
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
  • How far do you have drive for the two companies to charge the same?
  •            .75M + 20 = .40M + 27
  •            .35M + 20 = 27
  •                     .35M = 7
  •                         M = 20
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
  • If M = 20, find C.
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
  •   If M = 20, find C.
  • C = .75(20) + 20
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Applications of Graphs
  • Find where the two lines intersect.  Label the point.
  •   If M = 20, find C.
  • C = .75(20) + 20
  •                         C = 35
  • The two lines intersect at (20, 35).
  • Both companies charge $35 when you drive 20 miles.
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"When does Wrecker charge more..."







  • When does Wrecker charge more than Caddie?
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"What are the cost intercepts..."







  • What are the cost intercepts for Wrecker and Caddie?  What do they mean?
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"What does the slope of..."







  • What does the slope of each line mean in terms of the problem?
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 Introduction to Exponents
  • The population of Shanghai was 10,820,000 in 1974.  If the population increased by 1% each year, complete the table below.
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 Introduction to Exponents
  • The population of Shanghai was 10,820,000 in 1974.  If the population increased by 1% each year, complete the table below.
  • For 1975:
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 Introduction to Exponents
  • The population of Shanghai was 10,820,000 in 1974.  If the population increased by 1% each year, complete the table below.
  • For 1975: 10820000 + (.01)10820000 =
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 Introduction to Exponents
  • The population of Shanghai was 10,820,000 in 1974.  If the population increased by 1% each year, complete the table below.
  • For 1975: 10820000 + (.01)10820000 =
  •                                     (1.01)10820000 =
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 Introduction to Exponents
  • The population of Shanghai was 10,820,000 in 1974.  If the population increased by 1% each year, complete the table below.
  • For 1975: 10820000 + (.01)10820000 =
  •                                     (1.01)10820000 =
  •                                          10928200
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Introduction to Exponents
  • YR        CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76
  •   77
  •   78
  •    n
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Introduction to Exponents
  •   YR        CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76           (1.01)10928200
  •   77
  •   78
  •      n
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Introduction to Exponents
  • YR         CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76           (1.01)10928200
  •             (1.01)(1.01)10820000
  •     77
  •     78
  •    n
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Introduction to Exponents
  • YR        CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76           (1.01)10928200
  •            (1.01)(1.01)10820000
  •                  (1.01)210820000   11,037,482
  •   77
  •   78
  •    n
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Introduction to Exponents
  • YR        CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76           (1.01)210820000   11,037,482
  •   77           (1.01)310820000   11,147,857
  •   78           (1.01)410820000   11,259,335
  •    n
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Introduction to Exponents
  • YR        CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76           (1.01)210820000   11,037,482
  •   77           (1.01)310820000   11,147,857
  •   78           (1.01)410820000   11,259,335
  •    n            (1.01)n10820000              P
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Introduction to Exponents
  • YR        CALCULATION        POP
  •   75           (1.01)10820000     10,928,200
  •   76           (1.01)210820000   11,037,482
  •   77           (1.01)310820000   11,147,857
  •   78           (1.01)410820000   11,259,335
  •    n            (1.01)n10820000              P
  • What is the equation that relates Shanghai’s population and year?
  • P = (1.01)n10802000, n is the number of years since 1974.
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 Introduction to Exponents
  • Use the equation to find Shanghai’s population in 1985.
  • P = (1.01)n10802000, n is the number of years since 1974.
  • n = 1985 - 1974 = 11
  • P = (1.01)1110820000
  • P = (1.116)(1082000)
  • P = 12075120
  • The formula estimates that Shanghai’s population in 1985 was 12,075,120.
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 Negative Exponents
  • Use the following formula to find the monthly payments of a loan.             P = A         i              1 - ( 1 + i )-n P is the monthly payment A is the amount of the loan n is the number of payments i is the interest rate per month
  • Eddie Nerder can afford a $250 car payment at 6% annual interest rate for 36 months.  How expensive a car can he afford? ( Hint: I =.06 / 12 )
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 Negative Exponents







  •                 250 = A ( 0.0304 )
  •               8223 = A
  • Eddie can afford an $8,223 car.
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 Introduction to Algebraic Fractions
  • Suppose the cost of removing p percent of the particulate pollution from the exhaust gases at an industrial site is given by       c  =  6800p            100 - p
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 Introduction to Algebraic Fractions
  •       c  =  6800p            100 - p
  • Find the cost for p = 75
  •               c  =  6800(75)            100 - 75
  •          c  =  510000               25
  •          c = 20400
  • It would cost $20,400 to remove 75% of the particulate pollution.
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 Introduction to Algebraic Fractions
  •       c  =  6800p            100 - p
  • Find the cost for p = 100
  •               c  =  6800(100)            100 - 100
  •          c  =  680000               0
  •          c = undefined
  • The formula cannot compute the cost of removing all of the pollution.
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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t.


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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t
  • Find the height of the arrow for t = 2.
  • h = -16(22) + 160(2)
  • h = -16(4) + 160(2)
  • h = -64 + 320
  • h = 256
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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t
  • Compute the height for:
  • t = 2,   h = 256
  • t = 5,   h = 400
  • t = 8,   h = 256
  • t = 10, h = 0
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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t
  • According to the calculations above, when will the arrow reach its maximum height?
  •   t = 5
  • The arrow reaches the maximum height in 5 seconds.  The maximum height is 400 feet.
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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t
  • According to the calculations above, when will the arrow hit the ground?
  • When the arrow hits the ground the height, h, is zero.
  •                   t = 10
  • The arrow reaches the ground in 10 sec.
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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t
  • Graph the points obtained in a through d.
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 Introduction to Quadratics
  • William Tell shoots an arrow straight up with an initial velocity of 160 feet per second.  The height of the arrow is given by the equation             h = -16t2 + 160t
  • Graph the points obtained in a through d.
  • The points are: ( 2, 256)
  •                            ( 5, 400)
  •                            ( 8, 256)
  •                            (10, 0)
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Introduction to Quadratics
  •          h                                vertex






  •           intercept


  •                                                              t
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 Quadratic Graphs and Quadratics
  • Earl Black makes tea bags.  The cost and revenue of making and selling x million tea bags per month is          C = x2 - 38x + 400          R = -x2 + 78x. C and R are in thousands of dollars.Find the equation for profit.
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 Quadratic Graphs and Quadratics
  • Earl Black makes tea bags.  The cost and revenue of making and selling x million tea bags per month is          C = x2 - 38x + 400          R = -x2 + 78x. C and R are in thousands of dollars.Find the equation for profit.
  • P = R - C
  • P = (-x2 + 78x) - (x2 - 38x + 400)
  • P = -x2 + 78x - x2 + 38x - 400
  • P = -2x2 + 116x - 400
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 Quadratic Graphs and Quadratics
  • Graph the profit equation.  Explain what the vertex, x and p intercepts mean in terms of making tea bags.  Make sure you label the axis and use an appropriate scale.
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 Quadratic Graphs and Quadratics
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 Quadratic Graphs and Quadratics
  • P = -2x2 + 116x - 400
  • 1. The Vertex, (29, 1282), means;   If Earl Black sells 29 million tea bags    they will get a maximum profit of   1.282 million dollars.
  • 2. The x-intercepts, (3.675, 0) (54.33, 0),         mean; If Earl Black sells 3.675   million or 54.33 million tea bags they   will break even.
  • 3. The P-intercept, (0, -400), means;   The company’s start up costs.
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 Quadratic Graphs and Quadratics
  • Suppose Earl Black needs to make $500,000 in profit (P = 500).  Graph this line on the graph above and find out where the line intersects the graph.  Explain what the answers mean.
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 Quadratic Graphs and Quadratics
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 Quadratic Graphs and Quadratics
  • Suppose Earl Black needs to make $500,000 in profit (P = 500).  Graph this line on the graph above and find out where the line intersects the graph.  Explain what the answers mean.
  • Find x, if P = 500.
  • 500 = -2x2 + 116x - 400
  •     0 = -2x2 + 116x - 900
  •   a = -2, b = 116, c = -900
  •    x =9.228, 48.77
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 Quadratic Graphs and Quadratics
  • x = 9.228, 48.77
  • The line intersects the graph at (9.228, 500) and (48.77, 500).
  • If Earl Black needs to make $500,000 in Profit then they need to sell 9,228,000 or 48,770,000 tea bags.
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 Quadratic Graphs and Quadratics


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 Quadratic Graphs and Quadratics







  •      When does Earl Black make more than
  •      $500,000 in profit?
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Changes in Teaching Focus
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Visualization
  • in the broadest sense has always been important in mathematics
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Purpose of Multimedia Modules

  • Expectations by students
  • To present visualizations of concepts
  • To present animations
  • To require interactive participation of learner
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Materials
  • Web Page
  • ToolBook
  • PowerPoint
  • Excel
  • Flash
  • Merlot
  • ScreenWatch
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Web Page Resource
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Learning Objects
  • small bits of reusable materials
  • learning modules
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Merlot  - Learning Objects
http://www.merlot.org/Home.po
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Next Semester?
  • Ongoing project
  • Living book
  • Flash
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